National Occupational Competency Testing Institute (NOCTI) Carpentry Practice Exam

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How many 4-feet by 8-feet drywall sheets are required to cover the walls and ceiling of a room that is 12 feet wide, 8 feet long, by 8 feet high?

4 sheets

6 sheets

To determine how many 4-feet by 8-feet drywall sheets are needed to cover the walls and ceiling of a room that measures 12 feet wide, 8 feet long, and 8 feet high, we first need to calculate the total surface area that needs to be covered.

1. **Calculate the area of the walls:**

- The room has two pairs of opposite walls. The dimensions of each pair of walls are as follows:

- Two walls that are 12 feet wide and 8 feet high each have an area of \( 12 \times 8 = 96 \text{ square feet}\).

- Two walls that are 8 feet long and 8 feet high each have an area of \( 8 \times 8 = 64 \text{ square feet}\).

- Total wall area can be calculated by adding the areas of all the walls:

- Total area of the two wider walls: \( 2 \times 96 = 192 \text{ square feet}\).

- Total area of the two longer walls: \( 2 \times 64 = 128 \text{ square feet}\).

- Combined wall area: \( 192 + 128 =

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9 sheets

12 sheets

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